5. The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are -890.3 KJ mol-1, – 393.5 KJ mol-1 and – 285.8 KJ mol-1 respectively. Enthalpy of formation of CH4(g) will be

(i) – 74.8 KJ mol-1                                         

(ii) – 52.27 KJ mol-1

(iii) + 74.8 KJ mol-1                                 

(iv) + 52.26 KJ mol-1    

4 Views|Posted 9 months ago
Asked by Shiksha User
1 Answer
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9 months ago

5. As per question:

(i) CH4? +2O2? CO2? +2H2? O                                      ΔH1? =−890kJmol−1

(ii) C+O2? CO2?                                                        ΔH2? =−393.5kJmol−1

(iii) 2H2? +O2?2H2? O  ΔH3? =2* (−285.8)kJmol−1

Required reaction is

C+2H2? CH4 (g)? ; ΔHf? =?
From equation

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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