56.0L of nitrogen gas is mixed with excess of hydrogen gas and it is found that 20L of ammonia gas is produced. The volume of unused nitrogen gas is found to be _______L.

0 4 Views | Posted 3 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

          N2 (g)+3H2 (g)2NH3 (g)

    t =  0 56 l            Excess 0

               -10 l                     +20 l

    Final 46 l                  20 l

    Vol. of N2 (g) remained unreacted = 46 l

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