7.1. A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.

(a) What is the initial effect of the change on the vapour pressure?

(b) How do the rates of evaporation and condensation change initially?

(c) What happens when equilibrium is restored finally and what will be the final vapour pressure?

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A
alok kumar singh

0.01 M NaOH,

M = 1 * 10-2

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A
alok kumar singh

Kp = Kc (RT)Dng

36 * 10–2 = Kc (0.0821 * 300)–1

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A
alok kumar singh

A(g) ->B(g) + 1 2 (g)

Initial moles             n                         0             0

Eqb. moles               n(1 – a)   n α 2           na            

total moles =   n ( 1 + α 2 )

Eqb. pressure   ( 1 α ) p 1 + α 2 α p 1 + α 2 ( α 2 ) p 1 + α 2

K p = α p ( 1 + α 2 ) × [ α p ( 2 + α ) ] 1 2 ( 1 + α ) p 1 + α 2

K p = α 3 2 p 1 2 ( 2 + α ) 1 2 ( 1 α )        

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A
alok kumar singh

On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

A
alok kumar singh

Kindly go through the solution

 

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