7.12. A mixture of 1.57 mol of N2, 1.92 mol of H2 and 8.13 mol of NH3 is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant Kc for the reaction
N2?(g) + 3H2? (g) ? 2NH3? (g) is 1.7*102
Is this reaction at equilibrium? If not, what is the direction of net reaction?
7.12. A mixture of 1.57 mol of N2, 1.92 mol of H2 and 8.13 mol of NH3 is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant Kc for the reaction
N2?(g) + 3H2? (g) ? 2NH3? (g) is 1.7*102
Is this reaction at equilibrium? If not, what is the direction of net reaction?
According to the given equation, concentration quotient,
Qc = [NH3]2 / [N2] [ H2]3
= (8.13/20 mol L-1)2 / (1.57 / 20 mol L-1) x (1.92 / 20 mol L-1)3
= 2.38 x 103
The equilibrium constant (Kc) for the reaction = 1.7 x 10-2
As Qc ≠ Kc, the reaction is not in a state of equilibrium.
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry Ncert Solutions Class 11th 2023
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