7.12. A mixture of 1.57 mol of N2, 1.92 mol of H2 and 8.13 mol of NH3 is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant Kc for the reaction

N2?(g) + 3H2? (g) ? 2NH3? (g) is 1.7*102
Is this reaction at equilibrium? If not, what is the direction of net reaction?           

2 Views|Posted 9 months ago
Asked by Shiksha User
1 Answer
V
9 months ago

According to the given equation, concentration quotient,

Qc = [NH3]2 / [N2] [ H2]3

= (8.13/20 mol L-1)2 / (1.57 / 20 mol L-1) x (1.92 / 20 mol L-1)3

= 2.38 x 103

The equilibrium constant (Kc) for the reaction = 1.7 x 10-2

As Qc ≠ Kc, the reaction is not in a state of equilibrium. 

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Chemistry Ncert Solutions Class 11th 2023

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