7.23. At 1127 K and 1 atm pressure, a gaseous mixture of CO and CO2 in equilibrium with solid carbon has 90.55% CO by mass.
C (s) + CO2 (g) ⇌ 2CO (g)
Calculate Kc for this reaction at the above temperature.
7.23. At 1127 K and 1 atm pressure, a gaseous mixture of CO and CO2 in equilibrium with solid carbon has 90.55% CO by mass.
C (s) + CO2 (g) ⇌ 2CO (g)
Calculate Kc for this reaction at the above temperature.
Let the mixture has 100g as total mass.
So, The masses of CO and CO2? are 90.55g and 100 − 90.55 = 9.45 g respectively.
Therefore, te number of moles of CO
n= 90.55 / 28 ?= 3.234.
The number of moles of CO2?
n= 9.45 / 44 ?= 0.215.
The mole fraction of CO
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Chemistry Ncert Solutions Class 11th 2023
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