7.24. Calculate (a) ∆Gϴ and (b) the equilibrium constant for the formation of NO2 from NO and O2 at 298 K
NO (g) + ½ O2 (g)⇌ NO2 (g)
where
ΔfGϴ (NO2) = 52.0 kJ/mol
ΔfGϴ (NO) = 87.0 kJ/mol
ΔfGϴ (O2) = 0 kJ/mol
7.24. Calculate (a) ∆Gϴ and (b) the equilibrium constant for the formation of NO2 from NO and O2 at 298 K
NO (g) + ½ O2 (g)⇌ NO2 (g)
where
ΔfGϴ (NO2) = 52.0 kJ/mol
ΔfGϴ (NO) = 87.0 kJ/mol
ΔfGϴ (O2) = 0 kJ/mol
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1 Answer
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(a) ΔG? = Δf?G?(NO2?) − [Δf?G?(NO) + ½ ?Δf?G?(O2?)]
= 52.0 − 87.0 −1/2 × 0
= −35 kJ/mol
(b) logK = − ΔG? / 2.303RT = − 35×103 / (2.303 × 8.314 × 298) ?= 6.314
K = antilog (6.314)...more
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