7.32. Predict which of the following will have appreciable concentration of reactants and products:
a) Cl2 (g) ⇌2Cl (g) Kc = 5 *10–39
b) Cl2 (g) + 2NO (g) ⇌2NOCl (g) Kc = 3.7 * 108
c) Cl2 (g) + 2NO2 (g) ⇌2NO2Cl (g) Kc = 1.8
7.32. Predict which of the following will have appreciable concentration of reactants and products:
a) Cl2 (g) ⇌2Cl (g) Kc = 5 *10–39
b) Cl2 (g) + 2NO (g) ⇌2NOCl (g) Kc = 3.7 * 108
c) Cl2 (g) + 2NO2 (g) ⇌2NO2Cl (g) Kc = 1.8
Following conclusions can be drawn from the values of Kc .
(a) Since the value of Kc is very small, this means that the molar concentration of the products is very small as compared to that of the reactants.
(b) Since the value of Kc is quite large, this means that the molar concentration of the pro
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry Ncert Solutions Class 11th 2023
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