7.44. The ionization constant of phenol is 1.0 x 10-10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01 M in sodium phenolate?

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9 months ago

  C6H5OH? C6H5O- + H+

 

C6H5OH

C6H5O-

H+

Initial

0.05 M

0

0

After dissociation

0.05 –x

x

x

Ka = x2 / (0.05 - x) = 1.0 x 10-10

=> x2 / 0.05 = 1.0 x 10-10

=>           x2 = 5 x 10-12

=>             x= 2.2 x 10-6 M

In presence of 0.01 C6H5Na, suppose y is the amount of phenol dissociated, then at equilibrium

[C6H5OH] = 0.05 – y ≈ 0.05,

  [C6H5O-] = 0.01 + y ≈ 0.01 M, [H+] =

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0.01 M NaOH,

M = 1 * 10-2

pOH = 2

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A(g) ->B(g) + 1 2 (g)

Initial moles             n                         0       &nbs

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On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

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