7.47. It has been found that the pH of a 0.01 M solution of an organic acid is 4.15. Calculate the concentration of the anion, the ionization constant of the acid and its PKa.

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9 months ago

pH= −log [H+]=4.15

[H+]= antilog (−4.15)= 7.08*10−5

[A]= [H+]=7.08*10−5

The concentration of undissociated acid is 0.01−0.000071=0.009929M.

HA+H2? O? H3? O++A

Ka? = [H3? O+] [A] / [HA]? = (7.08*10−5) (7.08*10−5)? / 0.009929

= 5.05*10−7

pKa? = −logKa? = −log5.05*10−7 ≈ 6.3

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