7.49. Calculate the pH of the following solutions:
(a) 2g ofTlOH dissolved in water to give 2 litre of the solution
(b) 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of the solution
(c) 0.3 g of NaOH dissolved in water to give 200 mL of the solution
(d) l mL of 13.6 M HCl is diluted with water to give 1 litre of the solution.
7.49. Calculate the pH of the following solutions:
(a) 2g ofTlOH dissolved in water to give 2 litre of the solution
(b) 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of the solution
(c) 0.3 g of NaOH dissolved in water to give 200 mL of the solution
(d) l mL of 13.6 M HCl is diluted with water to give 1 litre of the solution.
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1 Answer
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(a) For 2g of TlOH dissolved in water to give 2 L of solution:
[TlOH] = [OH−] = (2×1)? / (2×221) = (1 / 221)? M
pOH = −log [OH]− = −log (1/221)?
= 2.35
pH = 14 – pOH = 14 − 2.35 = 11.65
(b) For 0.3 g of Ca (OH)2? dissolved in water to give 500 mL of solution:[OH−] = 2 [Ca (OH)2? ] = 2 (0.3×1000/500? ) = 1.2M
pOH = −log [OH−] = −log1.2 = 1.79pH= 14−pOH=14−1.79
=12.21
(c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution:[OH−]= [NaOH] = 0.3×1000/200? = 1.5M
pOH= −log [OH−] = &mi...more
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