7.59. The ionization constant of propanoic acid is 1.32 * 10–5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?                  

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9 months ago

Let the degree of ionization of propanoic acid be α. Then, representing propionic acid as HA, we have:

HA         +        H2O ⇔ H3O+    +    A

(.05−0.0α)≈0.5                         0.05α      0.05α

Ka= [H3O+] [A] / [HA]

    = (0.05α) (0.05α) / 0.05

    = 0.05α2

=> α = (Ka /0.05)1/2

            =1.63*1

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Chemistry Ncert Solutions Class 11th 2023

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