7.68. The solubility product constant of Ag2CrO4 and AgBr are 1.1*10−12and 5.0*10-13 respectively. Calculate the ratio of the molarities of their saturated solutions.

Silver chromate: Ag2CrO4? ? 2Ag+ + CrO42−? [Ag+] = 2s1? , CrO42−? = s1? Ksp? = (2s1? )2 (s1? ) = 4s3 = 1.1*10−12 s1? = 6.5 * 10−5 . (1) Silver bromide: AgBr? Ag+ + Br− [Ag+] = [Br−] = s2? Ksp? = (s2? ) * (s2? ) = (s2)2? = 5.0 * 10−13 s2? =7.07*10−7. (2) Divide equation (1) by equation (2) to obtain the ratio of the molarities of saturated solutions: ? s1/s2? = (6.50*10−5)/ (7.07*10−7)? = 91.9

**7.68. The solubility product constant of Ag₂CrO₄and AgBr are 1.110⁻¹²and 5.010^-13respectively. Calculate the ratio of the molarities of their saturated solutions.**

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Vishal Baghel | Contributor-Level 10

9 months ago

Silver chromate: Ag₂CrO₄? ? 2Ag⁺ + CrO₄^2−?
[Ag⁺] = 2s₁? , CrO₄²⁻? = s₁?
K_sp? = (2s₁? )² (s₁? ) = 4s³ = 1.1*10⁻¹²
s_1? = 6.5 * 10−5 . (1)
Silver bromide: AgBr? Ag⁺ + Br⁻
[Ag⁺] = [Br⁻] = s₂?
Ksp? = (s₂? ) * (s₂? ) = (s₂)²? = 5.0 * 10⁻¹³
s_2?=7.07*10⁻⁷. (2)
Divide equation (1) by equation (2) to obtain