7.70. The ionization constant of benzoic acid is 6.46*10−5 and Ksp for silver benzoate is 2.5*10−13. How many times is silver benzoate more soluble in a buffer of pH= 3.19 compared to its solubility in pure water?
7.70. The ionization constant of benzoic acid is 6.46*10−5 and Ksp for silver benzoate is 2.5*10−13. How many times is silver benzoate more soluble in a buffer of pH= 3.19 compared to its solubility in pure water?
Since pH=3.19,
[H3O+]=6.46*10−4M
C6H5COOH+H2O↔C6H5COO−+H3O
Ka= [C6H5COO−] [H3O+] / [C6H5COOH]
[C6H5COOH] / [C6H5COO−]= [H3O+] / Ka=6.46*10−4 / 6.46*10−5=10
Let the solubility of C6H5COOAg be xmol/L.
Then,
[Ag+]=x
[C6H5COOH]+ [C6H5COO−]=x
10 [C6H5COO−]+ [C6H5COO−]=x
[C6H5COO−]=x / 11
Ksp = [Ag+] [C
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0.01 M NaOH,
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36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry Ncert Solutions Class 11th 2023
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