7.9. Nitric oxide reacts with Br2and gives nitrosyl bromide as per reaction given below:

                                                2NO (g) + Br2 (g) ?? 2NOBr (g)
When 0.087 mole of NO and 0.0437 mole of Br2 are mixed in a closed container at constant temperature, 0.0518 mole of NOBr is obtained at equilibrium. Determine the compositions of the equilibrium mixture.

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    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    According to the equation, 2 moles of NO (g) react with 1 mole of Br (g) to form 2 moles of NOBr  (g). The composition of the equilibrium mixture can be calculated as follows:
    No. of moles of NOBr  (g) formed at equilibrium = 0.0518 mol
    No. of moles of NO (g) taking part in reaction = 0.0518 mol
    No. of moles of NO (g) left at equilibrium = 0.087 – 0.0518 = 0.0352 mol
    No. of moles of Br2  (g) taking part in reaction = 1/2 x 0.0518 = 0.0259 mol
    No. of moles of Br2  (g) left at equilibrium = 0.0437 – 0.0259 = 0.0178 mol
    The initial molar concentration and equilibrium molar concentration of different spe

    ...more

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