8.11. Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if oxidising agent is in excess. Justify this statement giving three illustrations.

36 Views|Posted 10 months ago
Asked by Shiksha User
1 Answer
V
10 months ago

The three examples are:

(i) When excess P4?   (reducing agent) reacts with F2? (oxidizing agent),  PF3?  is produced in which P has +3 oxidation number.
                        P4? (excess) + F2? → PF3?
But if fluorine is in excess,  PF5?  is formed in which P has oxidation number of +5.
           

...Read more

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Redox Reactions 2025

Chemistry Redox Reactions 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering