8.11 Write down the electronic configuration of: (i) Cr3+ (iii) Cu+ (v) Co2+ (vii) Mn2+ (ii) Pm3+ (iv) Ce4+ (vi) Lu2+ (viii) Th4+
8.11 Write down the electronic configuration of: (i) Cr3+ (iii) Cu+ (v) Co2+ (vii) Mn2+ (ii) Pm3+ (iv) Ce4+ (vi) Lu2+ (viii) Th4+
8.11 (i) The atomic number of Cr is 24 and the electronic configuration is [Ar] 3d54s1. When 3 electrons are removed, it becomes Cr3+. The electronic configuration of Cr3+: 1s2 2s2 2p6 3s2 3p6 3d3 Or [Ar]3d3
(ii) The atomic number of Pm is 61 and the electronic configuration is 1s2 2s2 2p6 3s2 3p6
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Chemistry Ncert Solutions Class 12th 2023
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