8.16. Why does the following reaction occur?
XeO64– (aq) + 2F– (aq) + 6H+(aq) → XeO3(g)+ F2(g) + 3H2O(l)
What conclusion about the compound Na4XeO6 (of which XeO64– is a part) can be drawn from the reaction?
8.16. Why does the following reaction occur?
XeO64– (aq) + 2F– (aq) + 6H+(aq) → XeO3(g)+ F2(g) + 3H2O(l)
What conclusion about the compound Na4XeO6 (of which XeO64– is a part) can be drawn from the reaction?
47 Views|Posted 10 months ago
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1 Answer
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Answered by
10 months ago
XeO64−? oxidizes F− and F− reduces XeO64−?
Hence, the given reaction occurs.
The oxidation number of Xe decreases from +8 to +6. The oxidation number of F increases from -1 to 0.
Thus, Na4? XeO6? is a stronger oxidising agent than F−.
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