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8.16. Why does the following reaction occur?

XeO64– (aq) + 2F– (aq) + 6H+(aq) → XeO3(g)+ F2(g) + 3H2O(l)

What conclusion about the compound Na4XeO6 (of which XeO64– is a part) can be drawn from the reaction?

0 31 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    XeO64−? oxidizes F− and F− reduces XeO64−?
    Hence, the given reaction occurs.
    The oxidation number of Xe decreases from +8 to +6. The oxidation number of F increases from -1 to 0.
    Thus,  Na4? XeO6? is a stronger oxidising agent than F−.

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