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8.34 Calculate the number of unpaired electrons in the following gaseous ions: Mn3+ , Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution?

0 28 Views | Posted 4 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    8.34 From the table given below:

    Mn3+ : 3d4

    unpaired electrons = 4

    V3+ : 3d2

    unpaired electrons =2

    Cr3+ : 3d3

    unpaired electrons= 3

    Ti3+ : 3d1

    unpaired electrons =1

    Cr3+ is most stable in aqueous solution because of half filled d-orbital.

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