8.4. Fluorine reacts with ice and results in the change:
H2O(s) + F2 (g) ——> HF (g) + HOF (g)
Justify that this reaction is a redox reaction.
8.4. Fluorine reacts with ice and results in the change:
H2O(s) + F2 (g) ——> HF (g) + HOF (g)
Justify that this reaction is a redox reaction.
59 Views|Posted 10 months ago
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10 months ago
Writing the O.N. of each atom above its symbol, we have,

here, the O.N. of F decreases from 0 in F2 to -1 in HF and increases from 0 in F2 to +1 in HOF. Therefore, F2 is both reduced as well as oxidised. Thus, it is a redox reaction and more specifically, it is a disproportionation reaction
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