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8.5. Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5, Cr2O72- and NO3-. Suggest structure of these compounds. Count for the fallacy.

0 14 Views | Posted 4 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    (a) H2? SO5?  by conventional method.
    Let x be the oxidation number of S
    2 (+1) + x + 5 (−2) = 0
    x = +8
    +8 oxidation state of S is not possible as S cannot have an oxidation number more than 6. The fallacy is overcome if we calculate the oxidation number from its structure HO−S (O2)−O−O−H.
    −1+X+2 (−2)+2 (−1)+1=0
    x=+6

    (b) Dichromate ion
    Let x be the oxidation number of Cr in dichromate ion
    2x+7 (−2)=−2
    x=+6
    Hence the oxidation number of Cr in dichromate ion is +6. This is correct and there is no fallacy.

    (c) Nitrate ion, by conventional method
    Let x be the oxidation number of N

    ...more

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