8.8 Calculate the 'spin only' magnetic moment of M2+(aq) ion (Z = 27).
8.8 Calculate the 'spin only' magnetic moment of M2+(aq) ion (Z = 27).
8.8 Given, Z=atomic number = 27 = [Ar]3d7 4s2
⇒ M2+ = [Ar]3d7
Hence, 3 unpaired electrons are present.
The spin only magnetic moment μ= √n(n+2)
Where n is the number of unpaired electrons.
Hence, μ =√(3*(3+2))
μ = √15 BM or μ = 3.87 BM
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