8. The reaction of cyanamide,NH2CN(s) with dioxygen was carried out in a bomb calorimeter and ?U was found to be -742,7 KJ-1 mol-1 at 298 K. Calculate the enthalpy change for the reaction at 298 K.
NH2CN (S) + 3/2O2(g) → N2(g) + CO2(g) + H2O(l)
8. The reaction of cyanamide,NH2CN(s) with dioxygen was carried out in a bomb calorimeter and ?U was found to be -742,7 KJ-1 mol-1 at 298 K. Calculate the enthalpy change for the reaction at 298 K.
NH2CN (S) + 3/2O2(g) → N2(g) + CO2(g) + H2O(l)
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1 Answer
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8. Given,
? U = – 742.7 KJ-1 mol-1
? ng = 2 – 3/2 = + 1/2 mol.
R = 8.314 x 10-3KJ-1 mol-1
T = 298 K
According to the relation? H =? U+? ng RT
? H = (- 742.7 KJ) + (1/2 mol) x (8.314 x10-3 KJ-1 m
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