9.9 Predict the number of unpaired electrons in the square planar [Pt(CN)4 ] 2– ion.
9.9 Predict the number of unpaired electrons in the square planar [Pt(CN)4 ] 2– ion.
-
1 Answer
-
In Pt [ (CN)4]2- ion:
Overall charge balance:
X + 4 (-1) = -2 X = + 2.
The oxidation state of Pt is + 2.
Since CN- is a strong field ligand, it causes pairing of the unpaired electrons.
Therefore, now the 2 unpaired electrons from 5d orbital get paired and it undergoes dsp2 hybridisation. It forms square planar geometry. Since all the electrons are paired,
No. of unpaired electrons = 0.
Similar Questions for you
CoCl3.NH3 + AgNO3
x = 5
In H2O (polar solvent) dibromophenol derivative and in CS2 (non-polar solvent moneobromo phenol derivate is obtained.
3d => 4d => 5d CFSE increases for the same ligands.
Factual
⇒ leaching methods is used for those metal in which metal is more soluble than impurities and these are Al, Au, Ag, low grade Cu
σ bonded organometallic compound ⇒ M – C
σ-bond
and in π – bonded organo metallic compound
M – C
π bond
In ferrocene, there is π-bond
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers