A 0.166 g sample of an organic compound was digested with conc. H2SO4 and then distilled with NaOH. The ammonia gas evolved was passed through 50.0 mL of 0.5 N H2SO4. The used acid required 30.0 mL of 0.25 N NaOH for complete neutralization. The mass percentage of nitrogen in the organic compound is ___________.

Meq of NH3 = Meq of used H2SO4 = Meq of NaOH = 0.25 * 30 = 7.5 Millmoles of N = millimoles of NH3 = 7.5 (As n factor = 1) Mass of nitrogen = 7.5 * 14 * 10-3 = 0.105 gm % of Nitrogen = 0 . 1 0 5 0 . 1 6 6 * 1 0 0 % = 6 3 . 2 5 % ~ 6 3 %

A 0.166 g sample of an organic compound was digested with conc. H₂SO₄ and then distilled with NaOH. The ammonia gas evolved was passed through 50.0 mL of 0.5 N H₂SO₄. The used acid required 30.0 mL of 0.25 N NaOH for complete neutralization. The mass percentage of nitrogen in the organic compound is ___________.

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Vishal Baghel | Contributor-Level 10

6 months ago

Meq of NH₃ = Meq of used H₂SO₄ = Meq of NaOH = 0.25 * 30 = 7.5

Millmoles of N = millimoles of NH₃ = 7.5 (As n factor = 1)

Mass of nitrogen = 7.5 * 14 * 10^-3 = 0.105 gm

% of Nitrogen = $\frac{0.105}{0.166} * 100 % = 63.25 % ~ 63 %$

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