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A 1.84 mg sample of polyhydric alcoholic compound ‘X’ of molar mass 92.0 g/mol gave 1.344mL of H2 gas at STP. The number of alcoholic hydrogens present in compound ‘X’ is_________.

0 2 Views | Posted 2 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    Mole of polyhydric alcohol =  1 . 8 4 × 1 0 − 3 9 2 = 2 . 0 × 1 0 − 5 m o l e .

    Mole of H2 gas produced = 1 . 3 4 4 2 2 4 0 0 = 6 . 0 × 1 0 − 5 m o l e .  

    No of -OH gp present =  6 . 0 × 1 0 − 5 2 . 0 × 1 0 − 5 = 3

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