A 25 watt bulb emits monochromatic yellow light of wavelength 0.57 μm. Calculate the rate of emission of quanta per second.
A 25 watt bulb emits monochromatic yellow light of wavelength 0.57 μm. Calculate the rate of emission of quanta per second.
-
1 Answer
-
Energy of one photon (E) = hc / λ
= (6.626 × 10-34 Js) x (3 × 108 m s-1) / (0.57 × 10-6 m) = 3.48 x 10-19 J
Rate of emission of quanta per second = Power / Energy = (25 watt) / (3.48 x 10-19 J)
= (25 Js-1) / (3.48 x 10-19 J) = 7.18 x 1019 s-1
Similar Questions for you
Kindly go through the answers
(7.00)
Kindly consider the following Image
In 4d orbital, n = 4 and
Radial nodes =
Radial nodes = 4 – 2 – 1 = 1
And angular nodes,
Here, number of unpaired electrons, n = 1
Spin only moment ;
= 173 × 10-2 B.M
=
= (At constant pressure)
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers