A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take <math> <mi>h</mi> <mo>=</mo> <mn>6.62</mn> <mo>×</mo> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>34</mn> </mrow> </mrow> </msup> <mi>J</mi> <mi>s</mi> </math> )

Power of bulb = 662 watt = 662 Js-1Energy of one photon = 6.62 * 10 - 34 * 3 * 10 8 300 * 10 - 9 = 6.62 * 10 - 19 J Number of photons emitted = 662 6.62 * 10 - 19 = 10 21 s - 1

A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take <math> <mi>h</mi> <mo>=</mo> <mn>6.62</mn> <mo>×</mo> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>34</mn> </mrow> </mrow> </msup> <mi>J</mi> <mi>s</mi> </math> )

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Chemistry Class 11th Structure of Atom

A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take $h = 6.62 \times 10^{- 34} J s$ )

Option 1 -

$10^{21} s^{- 1}$

Option 2 -

$10^{20} s^{- 1}$

Option 3 -

$10^{18} s^{- 1}$

Option 4 -

$10^{19} s^{- 1}$

2 Views | Posted a month ago

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 1

Detailed Solution:

Power of bulb = 662 watt = 662 Js^-1

Energy of one photon $= \frac{6.62 * 10^{- 34} * 3 * 10^{8}}{300 * 10^{- 9}}$ $\frac{^{}^{}}{^{}}$

$= 6.62 * 10^{- 19} J$

Number of photons emitted $= \frac{662}{6.62 * 10^{- 19}}$ $\frac{}{^{}}$

$= 10^{21} s^{- 1}$

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A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take $h = 6.62 \times 10^{- 34} J s$ )

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A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take h = 6.62 × 10 - 34 J s )

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A 662 watt bulb emits monochromatic light of wavelength 300 nm. The number of photons emitted per second by the bulb is (take $h = 6.62 \times 10^{- 34} J s$ )