A chloro compound “A”

(i) Forms aldehydes on ozonolysis followed by the hydrolysis.

(ii) When vaporized completely 1.53g of A, gives 448 mL of vapour at STP.

The number of carbon atoms in a molecule of compound A is________.

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Answered by

alok kumar singh | Contributor-Level 10

2 months ago

$\underset{C h l o r o c o m p o u n d}{\underset{?}{A}} \to_{(2) H_{2} O}^{(1) O_{3}} F o r m a l d e h y d e$

$↓$

Weight = 1.53 gm

V = 448 ml (STP)

Mole = $\frac{448}{22400} = \frac{w e i g h t}{m o l e c u l a r w e i g h t}$

$∴ \frac{1.53}{m o l e c u l a r w e i g h t} = \frac{1}{50}$

$∴$ Molecular weight of compound A = 50 × 1.53 = 76.5 gram

Molecular weight 76.5 = C_nH_2n-1Cl

$∴ C_{n} H_{2 n - 1} = 41$

or 12 n + 2n – 1 = 41

Molecular formula = C₃H₅Cl

Number of C- atoms = 3

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A chloro compound “A”

(i) Forms aldehydes on ozonolysis followed by the hydrolysis.

(ii) When vaporized completely 1.53g of A, gives 448 mL of vapour at STP.

The number of carbon atoms in a molecule of compound A is________.

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A chloro compound “A” (i) Forms aldehydes on ozonolysis followed by the hydrolysis. (ii) When vaporized completely 1.53g of A, gives 448 mL of vapour at STP. The number of carbon atoms in a molecule of compound A is________.

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A chloro compound “A”

(i) Forms aldehydes on ozonolysis followed by the hydrolysis.

(ii) When vaporized completely 1.53g of A, gives 448 mL of vapour at STP.

The number of carbon atoms in a molecule of compound A is________.