A gas (Molar mass = 280 g mol-1) was burnt in excess O2 in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298.0 K to 298.45K. If the heat capacity of calorimeter is 2.5 kJ K-1 and enthalpy of combustion of gas is 9 kJ mol-1 the amount of gas burnt is _____________g. (Nearest Integer)

14 Views|Posted 7 months ago
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1 Answer
V
7 months ago

Let x gm is burnt

Moles = x/280

Heat released by x/280 mol = 2.5 * 0.45 kJ

Heat released by 1 mol =  2 . 5 * 0 . 4 5 * 2 8 0 x = k J

Δ H = Δ U + Δ n g R T Δ H = Δ U            

9 = 2 . 5 * 2 8 0 * 0 . 4 5 x            

x = 35 gm

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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