A home owner uses 4.00 * 10³m³ of methane (CH?) gas, (assume CH? is an ideal gas) in a year to heat his home. Under the pressure of 1.0 atm and 300 K, mass of gas used is x * 10?g. The value of x is ______ (Nearest integer).
(Given R = 0.083 L atm K?¹mol?¹)

6 Views|Posted 7 months ago
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1 Answer
R
7 months ago

PV = nRT
n = PV/RT = (1 atm * 4*10? L) / (0.083 LatmK? ¹mol? ¹ * 300 K) = 1.6 * 10? mol
Mass = n * Molar Mass = 1.6 * 10? mol * 16 g/mol = 25.6 * 10? g ≈ 26 * 10? g

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Chemistry NCERT Exemplar Solutions Class 11th Chapter One 2025

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