A metal surface is exposed to 500nm radiation. The threshold frequency of the metal for photoelectric current is 4.3 × 1014 Hz. The velocity of ejected electron is_______× 105 ms-1. (Nearest integer)

 [Use : h = 6.63 × 10-34 Js, me = 9.0 × 10-31 kg]

0 8 Views | Posted 3 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    In photo-electric effect;

      h c λ = h v 0 + 1 2 m v 2             

      6 . 6 3 × 1 0 3 4 × 3 × 1 0 8 5 0 0 × 1 0 9 = ( 6 . 6 3 × 1 0 3 4 × 4 . 3 × 1 0 1 4 ) + 1 2 × 9 . 0 × 1 0 3 1 × v 2            

      v = ( 3 . 9 7 8 × 1 0 1 9 2 . 8 5 × 1 0 1 9 ) 4 . 5 × 1 0 3 1 = 2 5 × 1 0 1 0 = 5 × 1 0 5 m / s             

    Ans. = 5

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