A mixture of one mole each of $H_{2}, H e$ and $O_{2}$ each are enclosed in a cylinder of volume $V$ at temperature $T$ . If the partial pressure of $H_{2}$ is $2 a t m$ , the total pressure of the gases in the cylinder is:

Option 1 -

$14 a t m$

Option 2 -

6 atm

Option 3 -

$22 a t m$

Option 4 -

$38 a t m$

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

$P_{gas} = \frac{n_{gas} R T}{V}$

as $n, T$ & $V$ constant So

$P_{H_{2}} = P_{O_{2}} = P_{H_{θ}} = 2 a t m$

So, $P_{Total} = P_{H_{2}} + P_{O_{2}} + P_{H e} = 6 a t m$

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A mixture of one mole each of $H_{2}, H e$ and $O_{2}$ each are enclosed in a cylinder of volume $V$ at temperature $T$ . If the partial pressure of $H_{2}$ is $2 a t m$ , the total pressure of the gases in the cylinder is:

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A mixture of one mole each of H 2 , H e and O 2 each are enclosed in a cylinder of volume V at temperature T . If the partial pressure of H 2 is 2 a t m , the total pressure of the gases in the cylinder is:

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A mixture of one mole each of $H_{2}, H e$ and $O_{2}$ each are enclosed in a cylinder of volume $V$ at temperature $T$ . If the partial pressure of $H_{2}$ is $2 a t m$ , the total pressure of the gases in the cylinder is: