A plot of volume (V) versus temperature (T) for a gas at constant pressure is a straight line passing through the origin. The plots at different values of pressure are shown in Fig. 5.1. Which of the following order of pressure is correct for this gas?

(i) p₁ > p₂ > p₃ > p₄ 

(ii) p₁ = p₂ = p₃ = p₄

(iii) p₁ < p₂ < p₃ < p₄

(iv) p₁ < p₂ = p₃ < p₄

This is a multiple choice answer as classified in NCERT Exemplar

option  iii. p₁  < p₂ < p₃ < p₄

At a particular temperature, PV is constant

Therefore,   V ∝ $\frac{1}{\mathit{p}}$

So, as v₁ >  v₂  >  v₃  >  v₄   the order of pressure:  p₁  < p₂ < p₃ < p₄ .

 

<p><span data-teams="true">This is a multiple choice answer as classified in NCERT Exemplar</span></p><p>option<strong>&nbsp; </strong>iii. p_1&nbsp;&lt; p₂ &lt; p₃&lt; p₄</p><p>At a particular temperature, PV is constant</p><p>Therefore, &nbsp; V ∝<strong> <span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold-italic">p</mi> </mrow> </mrow> </mfrac> </math> </span></strong>&lt;!--- [endif]---&gt;&lt;!--- [endif]---&gt;</p><p>So, as v₁ &gt;&nbsp; v₂&nbsp; &gt;&nbsp; v₃&nbsp; &gt;&nbsp; v₄ &nbsp; the order of pressure:&nbsp; p_1&nbsp;&lt; p₂ &lt; p₃&lt; p₄.<br>&lt;!--- [endif]---&gt;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1751014762php546QNx.jpeg" alt="" width="231" height="238" loading="lazy"></picture></div></div><p>&nbsp;</p>

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