A sparingly soluble salt having general formula Ap+x Bq- y and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between the solubility and solubility product for such salt.
A sparingly soluble salt having general formula Ap+x Bq- y and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between the solubility and solubility product for such salt.
The equation can be written as-
Ap+x + Bq- y ? xAp+ (aq) + yBq-
S moles of A and B dissolves to give x S moles of Ap+ and y S moles of Bq-.
Ksp = [Ap+]x [Bq-]y = [x5]x [y5]y
= xx y y 5 x+y
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven 2025
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