According to Arrhenius equation rate constant k is equal to A^e - . Which of the following options represents the graph of in k vs  .

This is a Fill in the blanks Type Question as classified in NCERT Exemplar

Ans: Correct option A

Arrhenius equation Ae -   $\frac{\mathbf{}\mathbf{E}\mathbf{a}}{\mathbf{R}\mathbf{T}}$

K = rate constant

A= frequency factor

Ea= Activation Energy

R= gas constant

T= temperature

ln k = lnA - $\frac{\mathbf{E}\mathbf{a}}{\mathbf{R}\mathbf{T}}$

When the temperature rises, ln falls.

∴ ln kv/s $\frac{1}{\mathbf{T}}\mathrm{}$ , is a negative slope.

ln A is intercepted by k, and its magnitude decreases with time.

∴ Negative slope is obtained.

When compared to the other possibilities, T is increasing over time, which is incorrect.

ln k =  $\frac{-\mathbf{E}\mathbf{a}}{\mathbf{R}}$ $\frac{1}{\mathbf{T}}\mathbf{}$  + lnA

 

<p>This is a Fill in the blanks Type Question as classified in NCERT Exemplar</p><p><strong>Ans:&nbsp;</strong>Correct option A</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745906231php2fHKXm_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745906231php2fHKXm.jpeg" alt="" width="216" height="145"></picture></div><div><p>Arrhenius equation <strong>Ae -&nbsp;</strong><strong>&nbsp; <span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mi mathvariant="bold"> </mi> <mi mathvariant="bold">E</mi> <mi mathvariant="bold">a</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold">R</mi> <mi mathvariant="bold">T</mi> </mrow> </mrow> </mfrac> </math> </span></strong></p><p><strong>K</strong> = rate constant</p><p><strong>A</strong>= frequency factor</p><p><strong>Ea</strong>= Activation Energy</p><p><strong>R</strong>= gas constant</p><p><strong>T</strong>= temperature</p><p><strong>ln k = lnA - <span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mi mathvariant="bold">E</mi> <mi mathvariant="bold">a</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold">R</mi> <mi mathvariant="bold">T</mi> </mrow> </mrow> </mfrac> </math> </span></strong></p><p>When the temperature rises, <strong>ln</strong> falls.</p><p><strong>∴</strong> <strong>ln k</strong>v/s <span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold">T</mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal"> </mi> </math> </span>, is a negative slope.</p><p><strong>ln A</strong> is intercepted by <strong>k</strong>, and its magnitude decreases with time.</p><p><strong>∴</strong> Negative slope is obtained.</p><p>When compared to the other possibilities, T is increasing over time, which is incorrect.</p><p><strong>ln k =&nbsp; <span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mo>-</mo> <mi mathvariant="bold">E</mi> <mi mathvariant="bold">a</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold">R</mi> </mrow> </mrow> </mfrac> </math> </span><span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="bold">T</mi> </mrow> </mrow> </mfrac> <mi mathvariant="bold"> </mi> </math> </span></strong><strong>&nbsp;</strong><strong>+ lnA</strong></p></div></div><p>&nbsp;</p>

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