Al₂O₃ was leached with alkali to get X. The solution of X on passing of gas Y, forms Z. X, Y and Z respectively are:

Option 1 -

$X = N a [A l {(O H)}_{4}], Y = S O_{2}, Z = A l_{2} O_{3}$

Option 2 -

$X = A l {(O H)}_{3}, Y = C O_{2}, Z = A l_{2} O_{3}$

Option 3 -

$X = A l {(O H)}_{3}, Y = S O_{2}, Z = A l_{2} O_{3} . x H_{2} O$

Option 4 -

$X = N a [A l {(O H)}_{4}], Y = C O_{2}, Z = A l_{2} O_{3} . x H_{2} O$

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

Leaching of Al₂O₃ with alkali;

$\begin{array}{l} A l_{2} O_{3} (s) + 2 N a O H (a q) + 3 H_{2} O (l) \to 2 N a [A l {(O H)}_{4}] (a q) \\ X \end{array}$

$\begin{array}{l} 2 N a [A l {(O H)}_{4}] (a q) + 2 C O_{2} (g) \to A l_{2} O_{3} . x H_{2} O (s) + 2 N a H C O_{3} (a q) \\ X Y Z \end{array}$

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Al₂O₃ was leached with alkali to get X. The solution of X on passing of gas Y, forms Z. X, Y and Z respectively are:

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Al2O3 was leached with alkali to get X. The solution of X on passing of gas Y, forms Z. X, Y and Z respectively are:

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Al₂O₃ was leached with alkali to get X. The solution of X on passing of gas Y, forms Z. X, Y and Z respectively are: