An homogeneous ideal gaseous reaction A B 2 ( g ) ? A ( g ) + 2 B ( g )  is carried out in a 25 litre flask at 27°C. The initial amount of AB2 was 1 mole and the equilibrium pressure was 1.9atm. The value of Kp is x × 10-2. The value of x is-----------. (Integer answer).

[R = 0.08206 dm3 atm K-1 mol-1]

0 7 Views | Posted 3 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    AB2 (g)? A (g)+2B (g)

    Initial1 mole -

    At equilirbium 1-x mole x mole2x mole

    V = 25 L and

    T = 300 K.

    At equilibrium, P = 1.9 atm

    Total moles at equilibrium, n = 1 + 2x

    V = 25 L

    T = 300 K

    Using, PV = nRT

    1.9 × 25 = (1 + 2x) × 0.08206 × 300

    x = 0.465

    Now;Partial pressure of AB2 at equilibrium = 0.5351.93×1.9atm

    Using ; Kp=PA.PB2PAB2

    Kp= (0.465×1.91.93) (2×0.4651.93×1.9)20.5351.93×1.9 = 0.728

    KP = 0.73

    Kp = 73 × 10-2

    So; x = 73

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