An homogeneous ideal gaseous reaction A B 2 ( g ) ? A ( g ) + 2 B ( g )  is carried out in a 25 litre flask at 27°C. The initial amount of AB2 was 1 mole and the equilibrium pressure was 1.9atm. The value of Kp is x * 10-2. The value of x is-----------. (Integer answer).

[R = 0.08206 dm3 atm K-1 mol-1]

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7 months ago

AB2 (g)? A (g)+2B (g)

Initial1 mole -

At equilirbium 1-x mole x mole2x mole

V = 25 L and

T = 300 K.

At equilibrium, P = 1.9 atm

Total moles at equilibrium, n = 1 + 2x

V = 25 L

T = 300 K

Using, PV = nRT

1.9 * 25 = (1 + 2x) * 0.08206 * 300

x = 0.465

Now;Partial pressure of AB2 at equilibrium = 0.5351.93*1.9atm

Using ; Kp=PA.PB2PAB2

Kp= (0.465*1.91.93) (2*0.4651.93*1.9)20.5351.93*1.9 = 0.728

KP = 0.73

Kp = 73 * 10-2

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Chemistry Chemical Equilibrium 2025

Chemistry Chemical Equilibrium 2025

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