An ideal gas is allowed to expand against a constant pressure of 2 bar from 10 L to 50 L in one step. Calculate the amount of work done by the gas. If the same expansion were carried out reversibly, will the work done be higher or lower than the earlier case?
An ideal gas is allowed to expand against a constant pressure of 2 bar from 10 L to 50 L in one step. Calculate the amount of work done by the gas. If the same expansion were carried out reversibly, will the work done be higher or lower than the earlier case?
This is a Short Answer Type Questions as classified in NCERT Exemplar
We know that the amount of work done =-pext? V
On substituting the values in the formula, we get,
-2bar* (50-10)L=-80Lbar
According to the described problem,1 LBar = 100J
Therefore, -80 L bar= (-80*100)= -8000J
= -8kJ, which is the amo
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