An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO₃ [Carius Method], the percentage of chlorine in compound A is _______ when it forms 0.3849 g of AgCl (Round off to the Nearest integer) (Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)
An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO₃ [Carius Method], the percentage of chlorine in compound A is _______ when it forms 0.3849 g of AgCl (Round off to the Nearest integer) (Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)
Organic compound + Cl? → A (Containing Cl)
5gm
A + AgNO? → AgCl
0.5 gm → 0.3849gm
Mole of AgCl = 0.3849 / 143.32
Mass of Cl = (0.3849/143.32) * 35.5 ≈ 0.095
% of Cl in A = (0.095/0.5) * 100 = 19%
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Chemistry Ncert Solutions Class 12th 2023
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