An organic compound P contains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium meta, but its 2.9g combine with Xg of bromine (to give dibromo addition product). Find out value of (Y-X). (Where Y is total number of possible isomers of given organic compound P)

[Atomic mass : Br = 80]

Molecular formula from calculation comes to be C₃H₆O i.e., it stands for the following compounds.

No addition reaction with Br₂

 

VD × 2 = MM         = 29 × 2 = 58

$?$  58 g of ether combines with 2 × 80g Br₂

$?$ 2.9 g of ether will combines with   $\frac{2\times 80}{58}\times 2.9=8gofBromine$

Y = 9 and X = 8

Y - X = 9 - 8 = 1

 

<p>Molecular formula from calculation comes to be C₃H₆O i.e., it stands for the following compounds.</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757502164phpenUXIW.jpeg" alt="" width="391" height="88" loading="lazy"></picture></div></div><p>No addition reaction with Br₂</p><p>&nbsp;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757502205phpB7lraY.jpeg" alt="" width="417" height="341" loading="lazy"></picture></div></div><p>VD × 2 = MM&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = 29 × 2 = 58</p><p><span contenteditable="false"> <math> <mrow> <mo>? </mo> </mrow> </math> </span>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1819027810"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;58 g of ether combines with 2 × 80g Br₂</p><p><span contenteditable="false"> <math> <mrow> <mo>? </mo> </mrow> </math> </span>2.9 g of ether will combines with &lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1027" DrawAspect="Content" ObjectID="_1819027812"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;<span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>2</mn> <mo>×</mo> <mn>8</mn> <mn>0</mn> </mrow> <mrow> <mn>5</mn> <mn>8</mn> </mrow> </mfrac> <mo>×</mo> <mn>2</mn> <mo>.</mo> <mn>9</mn> <mo>=</mo> <mn>8</mn> <mi>g</mi> <mtext> </mtext> <mtext> </mtext> <mi>o</mi> <mi>f</mi> <mtext> </mtext> <mtext> </mtext> <mi>B</mi> <mi>r</mi> <mi>o</mi> <mi>m</mi> <mi>i</mi> <mi>n</mi> <mi>e</mi> </mrow> </math> </span></p><p>Y = 9 and X = 8</p><p>Y - X = 9 - 8 = 1</p><p>&nbsp;</p>

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