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At 2 5 ° C  and 1 atm pressure, the enthalpies of combustion are as given below:

The enthalpy of formation of ethane is

Option 1 -

+54.0 kJ mol-1 

Option 2 -

-68.0 kJ mol-1

Option 3 -

-86.0 kJ mol-1

Option 4 -

+97.0 kJ mol-1

0 2 Views | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    4 weeks ago
    Correct Option - 3


    Detailed Solution:

    2 C ( s ) + 2 H 2 ( g ) ? ?     → C 2 H 6 ( g ) Δ H = Δ H f ( C 2 H 6 )

    Δ H f ( C 2 H 6 ) = [ 2 × ( − 3 9 4 ) ] + [ 3 × ( − 2 8 6 ) ] − [ 1 × ( − 1 5 6 0 ) ] K J / m o l e

    = (-788 – 858 + 1560) KJ/mole = -86 kJ/mole

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