At   2 5 ° C and 1 atm pressure, the enthalpy of combustion of benzene (I) and acetylene (g) are -3268 kJ mol-1 and -1300 kJ mol-1, respectively. The change in enthalpy for the reaction 3C2H3(g) ® C6H6(I), is

Option 1 -

+324 kJ mol-1

Option 2 -

+632 kJ mol-1

Option 3 -

-632 kJ mol-1

Option 4 -

-732 kJ mol-1

0 4 Views | Posted 3 months ago
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  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 months ago
    Correct Option - 3


    Detailed Solution:

    Δ H = 3 ( Δ H c o m b ) C 2 H 2 ( g ) ( Δ H c o m b ) C 6 H 6 ( l )

    = 1 3 0 0 × 3 ( 3 2 6 8 ) k J / m o l e

    = ( 3 9 0 0 + 3 2 6 8 ) k J / m o l e

    = 6 3 2 k J / m o l e

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