At 20.0mL solution containing 0.2g impure H2O2 reacts completely with 0.316g of KMnO4 in acid solution. The purity of H2O2 (in %) is (mol. wt. of H2O2=34 ; mol. wt. of KMnO4=158

1 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago

eq of H2O2= eq of KMnO4

=0.316158*5=0.01=0.01*170.2*100=85%

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.8L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering