Ask & Answer Question

Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve Class 12th Oxidation Number Redox Reactions Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight

On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid $(C)$ is:

Option 1 -

Option 2 -

Option 3 -

Option 4 -

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

$2 P b {({N O}_{3})}_{2} \overset{Δ}{?} 2 P b O + 2 {N O}_{2} + O_{2}$

$2 {N O}_{2} ? N_{2} O_{4}$ colourless

$N_{2} O_{4} + 2 N O ? 2 N_{2} O_{3}$

Oxidation state in $N_{2} O_{3}$ is +3

0 Upvotes 0 Downvotes

Similar Questions for you

At $20.0 m L$ solution containing $0.2 g$ impure $H_{2} O_{2}$ reacts completely with $0.316 g$ of ${K M n O}_{4}$ in acid solution. The purity of $H_{2} O_{2}$ (in %) is (mol. wt. of $H_{2} O_{2} = 34$ ; mol. wt. of ${K M n O}_{4} = 158$ )

alok kumar singh

eq of $H_{2} O_{2} =$ eq of ${K M n O}_{4}$

$\begin{array}{r} = \frac{0.316}{158} * 5 = 0.01 \\ = \frac{0.01 * 17}{0.2} * 100 = 85 % \end{array}$

Consider the following equations :

$2 {F e}^{2 +} + H_{2} O_{2} \to x A + y B$ (in basic medium)

(in acidic medium)

$2 {M n O}_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} \to x^{'} C + y^{'} D + z^{'} E$

(in acidic medium)

The sum of the stoichiometric coefficients $x, y, x^{'}, y^{'}$ and $z^{'}$ for products $A, B, C, D$ and $E$ , respectively, is

alok kumar singh

Sol. first order reaction

$K = \frac{2.303}{t} l o g ? \frac{a_{0}}{a_{0} - x}$

$K = \frac{2.303}{90} l o g ? \frac{a_{0}}{0.25 a_{0}}$

$= 0.0154$

$\begin{array}{r} t = 60 % = \frac{2.303}{K} l o g ? \frac{a_{0}}{a_{0}} \dots . (2) \\ = \frac{2.303}{0.0154} \times (1 - 0.602) = 59.51 m i n s \approx 60 \end{array}$

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid $(C)$ is:

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid $(C)$ is: