On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:

Option 1 - <p>+4&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 2 - <p>+3&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>+2<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>+5</p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 2
Detailed Solution:

2PbNO32? Δ2PbO+2NO2+O2

2NO2? N2O4 colourless

N2O4+2NO? 2N2O3

Oxidation state in N2O3 is +3

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

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