At 25°C, 50 g of iron reacts with HCl to form FeCl?. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is __________ J. (Round off to the nearest integer).
[Given: R= 8.314 J mol?¹ K?¹. Assume hydrogen is an ideal gas]
[Atomic mass of Fe is 55.85u]
At 25°C, 50 g of iron reacts with HCl to form FeCl?. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is __________ J. (Round off to the nearest integer).
[Given: R= 8.314 J mol?¹ K?¹. Assume hydrogen is an ideal gas]
[Atomic mass of Fe is 55.85u]
The reaction is Fe (s) + 2HCl (aq) → FeCl? (aq) + H? (g). 50 g of Fe corresponds to 0.89 moles, which produces 0.89 moles of H? (g). The work done by the gas is calculated using W = -Δn_gasRT. The work done by the gas is the positive value, 2218 J.
Answer: 2218 J
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Ncert Solutions Class 11th 2023
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