At 298 K, the standard electrode potentials of Cu²⁺/Cu, Zn²⁺ /Zn, Fe²⁺ /Fe and Ag⁺ /Ag are 0.34 V, -0.76 V, -0.44 V and 0.80 V, respectively. On the basis of standard electrode potential, predict which of the following reaction can not occur?

Option 1 - <p>CuSO₄(aq) + Zn(s) → ZnSO₄(aq) + Cu(s)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>CuSO₄(aq) + Fe(s) → FeSO₄(aq) + Cu(s)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>FeSO₄(aq) + Zn(s) → ZnSO₄(aq) + Fe(s)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>2CuSO₄(aq) + 2Ag(s) → 2Cu(s) + Ag₂SO₄(aq)</p> <p><br><!--[endif]--></p>
4 Views|Posted 5 months ago
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1 Answer
V
5 months ago
Correct Option - 4
Detailed Solution:

Silver will not be able to reduce Cu²? to Cu.

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Similar Questions for you

ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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Chemistry Electrochemistry 2025

Chemistry Electrochemistry 2025

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