At 500 K, equilibrium constant, Kc , for the following reaction is 5.
(g) + (g) ⇌ HI (g)
What would be the equilibrium constant Kc for the reaction
2HI(g) ⇌ H2 (g) + I2 (g)
(i) 04
(ii) 4
(iii) 25
(iv) 5
At 500 K, equilibrium constant, Kc , for the following reaction is 5.
(g) + (g) ⇌ HI (g)
What would be the equilibrium constant Kc for the reaction
2HI(g) ⇌ H2 (g) + I2 (g)
(i) 04
(ii) 4
(iii) 25
(iv) 5
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: option (i)
If the equation is multiplied by 2, the equilibrium constant for the new equation is the square of K it means we must do the square of 5 that is 25. Then and on reversing the reaction the value of the equilibrium cons
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36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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