Atomic number of Mn, Fe, Co and Ni are 25, 26 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?

A: [MnCl6]3- 

B: [FeF6]3- 

C: [CoF6]3- 

D: [Ni(NH3)6]2+

0 4 Views | Posted 3 months ago
Asked by Shiksha User

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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Multiple Choice Questions as classified in NCERT Exemplar

    Ans: Correct option: A and C

    The outer octahedral complexes are weak ligands, number of pairing electrons and high spinning potential.

    [MnCl6]3-   - electronic configuration of Mn = 3d5,4s2. Shifting the valence electrons become 

    Mn3+ ,3d4 and number of unpaired electrons is 4.

    [FeF6]3- - electronic configuration of Fe = 3d6,4s2. Shifting the valence electrons become

    Fe3+ ,3d5 and the number of unpaired electrons is 5.

    [CoF6]3 - electronic configuration of Co  =  3d7,4s2 shifting the valence electrons become

     Fe3+ ,3d6

    ...more

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