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Boiling point of a 2% aqueous solution of a non-volatile solute A is equal to the boiling point of 8% aqueous of non-volatile solute B. The relation between molecular weights of A and B is

Option 1 -

MA = 4MB

Option 2 -

MB = 4M4

Option 3 -

MA = 8MB

Option 4 -

MB = 8MA

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 2


    Detailed Solution:

    For A : 100 gm solution 2 gm solute A

    ∴ M o l a l i t y = 2 / M A 0 . 0 9 8

    For B : 100 gm solution 8 gm solute B

    ∴ M o l a l i t y = 8 / M B 0 . 0 9 2

    1 4 . 2 6 1 = M A M B

    ∴ M B = 4 . 2 6 1 × M A

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