C(s) + O2(g) ® CO2(g) + 400 kJ

C(s) + 1 2 O 2 ( g ) C O ( g ) + 1 0 0 k J  

When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into 'CO' and the remaining is converted into 'CO2'.

The heat generated when 0.6 kg of coal is burnt is___________.

Option 1 - <p>1600 kJ</p>
Option 2 - <p>3200 kJ</p>
Option 3 - <p>&nbsp;4400 kJ</p>
Option 4 - <p>6600 kJ</p>
6 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago
Correct Option - 4
Detailed Solution:

Mass of pure carbon in coal = 0.6 * 1000gm * 6 0 1 0 0 = 3 6 0 g m  

Mass of carbon converted into CO = 6 6 0 1 0 0 * 3 6 0 = 2 1 6 g m M o l = 2 1 6 1 2 = 1 8  mole of carbon

Mass of carbon converted into CO2 = 360 – 216 = 144gm Þ Mole = 1 4 4 1 2 = 1 2  mole of carbon.

C (s) + O2 (g) -> CO2 (g) + 400KJ

Mole – 12 for CO2 production, Hence total energy produced = 400 * 12 = 4800KJ

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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